Suppose you drop a ball from a window 15 meters above the ground. The ball bounces to 70% of its previous height with each bounce. What is the total number of meters (rounded to the nearest tenth) the ball travels between the time it is dropped and the eighth bounce? Hint: cap s sub n equals start fraction a sub one left parenthesis one minus r to the power of n end power right parenthesis over one minus r end fraction comma r ≠ 1, where a1 is the first term and r is the common ratio.

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26 August, 09:05

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Zion Mccall · Answer 1

25 + 2*25*3/4 + 2*25 * (3/4) ^2 + ...

= 25 + 2*25 * (3/4 + (3/4) ^2 + (3/4) ^3 + (3/4) ^4 + (3/4) ^5 + (3/4) ^6 + ... (3/4) ^9)

= 163.7 meters