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Darryl Erickson
Mathematics
13 April, 05:18
1²+3²+4² + ... + (2n-2) ² = ⅓n (2n-1) (2n+1)
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Jimena Lester
13 April, 05:26
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1² + 3² + 4² + 4 (n - 1) ² = ¹/₃n (2n - 1) (2n + 1)
1² + 3² + 4² + (2n - 2) ² = ¹/₃n (2n - 1) (2n + 1)
1 + 9 + 16 + (2n - 2) (2n - 2) = ¹/₃n (2n (2n + 1) - 1 (2n + 1))
10 + 16 + (2n (2n - 2) - 2 (2n - 2)) = ¹/₃n (2n (2n) + 2n (1) - 1 (2n) - 1 (1) 16 + (2n (2n) - 2n (2) - 2 (2n) + 2 (2)) = ¹/₃n (4n² + 2n - 2n - 1)
26 + (4n² - 4n - 4n + 4) = ¹/₃n (4n² - 1)
26 + (4n² - 8n + 4) = ¹/₃n (4n² - 1)
26 + 4n² - 8n + 4 = ¹/₃n (4n²) - ¹/₃n (1)
4n² - 8n + 4 + 26 = 1¹/₃n³ - ¹/₃n
4n² - 8n + 30 = 1¹/₃n³ - ¹/₃n
+ ¹/₃n + ¹/₃n
4n² - 7²/₃n + 30 = 1¹/₃n³
-1¹/₃n³ + 4n² - 7²/₃n + 30 = 0
-3 (-1¹/₃n³ + 4n² - 7²/₃n + 30) = - 3 (0)
-3 (-1¹/₃n³) - 3 (4n²) - 3 (-7²/₃n) - 3 (30) = 0
4n³ - 12n² + 23n - 90 = 0
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