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15 July, 02:17

For what value (s) of k will the relation not be a function?

A = { (3k-4, 16), (4k, 32) }

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  1. 15 July, 02:25
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    We won't have a function if for same value of x in (x, y) we get different values y.

    So first step: figure out k so that the first coordinate (x) is the same:

    3k-4=4k | solve for k

    k = - 4

    no check the values y for the elements of the relation

    x = 3k-4 = - 12-4=-16

    so at - 16 we get (-16,16) and (-16, 32), which mean for k=-4 the relation is not a function.

    Let me know if you have any questions.
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