For what value (s) of k will the relation not be a function?

A = { (3k-4, 16), (4k, 32) }

Question

Devin Bond

Mathematics

15 July, 02:17

For what value (s) of k will the relation not be a function?

A = { (3k-4, 16), (4k, 32) }

+4

Answers (1)

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Addison Lopez · Answer 1

We won't have a function if for same value of x in (x, y) we get different values y.

So first step: figure out k so that the first coordinate (x) is the same:

3k-4=4k | solve for k

k = - 4

no check the values y for the elements of the relation

x = 3k-4 = - 12-4=-16

so at - 16 we get (-16,16) and (-16, 32), which mean for k=-4 the relation is not a function.

Let me know if you have any questions.

For what value (s) of k will the relation not be a function?A = { (3k-4, 16), (4k, 32) }

For what value (s) of k will the relation not be a function?

A = { (3k-4, 16), (4k, 32) }