Having serious block because of the units The density of mercury is 13.6 g/cm3. What approximate mass of mercury is required to fill a 33 ounce bottle? An ounce is approximately 30 cm^3. I know Density = m/v but Im getting. 013464 as the answer when the answer should be 13.464

Question

Ali Hammond

Mathematics

30 November, 21:45

Having serious block because of the units The density of mercury is 13.6 g/cm3. What approximate mass of mercury is required to fill a 33 ounce bottle? An ounce is approximately 30 cm^3. I know Density = m/v but Im getting. 013464 as the answer when the answer should be 13.464

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Answers (1)

Know the Answer?

Leroy Cole · Answer 1

I would approach the problem like this:

1 oz bottle ... 30cm^3

33 oz bottle ... xcm^3

in a 33 oz bottle will be x=33*30=990cm^3

density=mm/v

13.6g/cm^3 = m / 990cm^3

m = 13.6 * 990=13464 g

or 13.464 kg in a 33 oz bottle