A warehouse's rectangular ceiling measures 12 meters by 18 meters, and is covered by acoustic tile squares which are one meter on a side. Each piece of tile weighs a quarter of a kilogram. What will be the total weight of the tile required to cover the ceiling?

The first thing to do is find the rectangular warehouse area.

We have then:

A = (12) * (18) = 216

A = 216 m ^ 2

We now look for the area of each acoustic tile square:

A ' = (1) ^ 2 = 1

A ' = 1 m ^ 2

We look for acoustic tile squares number:

N = (A) / (A ')

N = (216) / (1)

N = 216

Finally we look for the total weight:

W = (1/4) * (216)

W = 54 Kg

Answer:

The total weight of the tile required to cover the ceiling is:

W = 54 Kg