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David Matthews
Mathematics
31 August, 04:16
X^3 + 5x^2 - 8x^2 - 40x + 7x + 35
+3
Answers (
1
)
Mariam Bentley
31 August, 04:23
0
Remark
x - 1 is a root.
Proof
x - 1 = 0
x = 1
(1) ^3 + 5 (1) ^2 - 8 (1) ^2 - 40 (1) + 7 (1) + 35
1 + 5 - 8 - 40 + 7 + 35
6 + 7 + 35 - 48 = 0
Solution
Divide x - 1 into the original equation.
x^3 + 5x^2 - 8x^2 - 33x + 35
x - 1 || x^3 - 3x^2 - 33x + 35 || x^2 - 2x - 35
x^3 - x^2
-2x^2 - 33x
-2x^2 + 2x
- 35x + 35
-35x + 35
0
x^2 - 2x - 35 factors into (x - 7) (x + 5)
Complete factorization
(x - 1) (x - 7) (x + 5)
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