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31 August, 04:16

X^3 + 5x^2 - 8x^2 - 40x + 7x + 35

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Answers (1)
  1. 31 August, 04:23
    0
    Remark

    x - 1 is a root.

    Proof

    x - 1 = 0

    x = 1

    (1) ^3 + 5 (1) ^2 - 8 (1) ^2 - 40 (1) + 7 (1) + 35

    1 + 5 - 8 - 40 + 7 + 35

    6 + 7 + 35 - 48 = 0

    Solution

    Divide x - 1 into the original equation.

    x^3 + 5x^2 - 8x^2 - 33x + 35

    x - 1 || x^3 - 3x^2 - 33x + 35 || x^2 - 2x - 35

    x^3 - x^2

    -2x^2 - 33x

    -2x^2 + 2x

    - 35x + 35

    -35x + 35

    0

    x^2 - 2x - 35 factors into (x - 7) (x + 5)

    Complete factorization

    (x - 1) (x - 7) (x + 5)
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