A radio signal travels at 3.00 • 10^8 meters per second. How many seconds will it take for a radio signal to travel from a satellite to the surface of Earth if the satellite is orbiting at a height of 3.54 • 10^7 meters? Show your work.

would the answer be rate=3*10^8m/s

distance=3.6*10^7m

time=distance/rate=3.6/30?

The answer is 0.118 seconds.

The velocity (v) is the distance (d) divided by time (t):

v = d : t

It is given:

v = 3.00 * 10⁸ meters per second

d = 3.54 * 10⁷ meters

It is unknown:

t = ?

If:

v = d : t

Then:

t = d : v

t = 3.54 * 10⁷ meters : 3.00 * 10⁸ meters/second

t = 1.18 * 10⁻¹ seconds

t = 0.118 seconds

Therefore, radio signal will travel from a satellite to the surface ofEarth 0.118 seconds.