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28 January, 06:32

What is the inverse of y=9x^2-4

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  1. 28 January, 06:51
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    You have y in terms of x. Solve for x in terms of y.

    y = 9x^2 - 4

    Add 4 to both sides:

    y + 4 = 9x^2

    Divide both sides by 9:

    (y+4) * (1/9) = x^2

    Take the square root of both sides:

    (y+4) ^ (1/2) * (1/9) ^ (1/2) = x

    (y+4) ^ (1/2) * 1/3 = x

    x = 1/3 (y+4) ^ (1/2)
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