A bag contains 6 red 4 blue and 8 green marbles how many marbles of each color shoul be added so that the total number of marbles is 27 but the probability of randomly selecting one marble of each color remains unchanged

3 red, 2 blue and 4 green marbles.

Step-by-step explanation:

Presently the bag contains 18 marbles.

Probability of selecting a red marble in the bag of 18 marbles = 6/18 = 1/3.

Probability of getting a blue is 2/9 and of getting green is 4/9.

So if we have 27 marbles the probability of a red must be 1/3 so we must have 1/3 * 27 = 9 reds.

In a similar calculation there would have to be 2/9 * 27 = 6 blues and

4/9 * 27 = 12 green marbles.

So we have to add 9-6 = 3 red, 6-4 = 2 blue and 12-8 = 4 green marbles.