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21 June, 13:36

How would you solve x^2 - 6x + 7=0 to complete the square and solve the quadratic equation?

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  1. 21 June, 13:47
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    The correct answers are x = 7 and x = - 1.

    In order to complete the square, you have to complete a process by which we make the equation a perfect square. To do this we need to follow the steps below.

    x^2 - 6x + 7 = 0

    Start by subtracting the constant away from the left side.

    x^2 - 6x = 7

    Now take half of the x term's coefficient and square it. Then you can add that to both sides. The x terms coefficient is - 6. Half of that is - 3. Then - 3 squared is 9. So we add 9 to both sides.

    x^2 - 6x + 9 = 16

    Now the left side is a perfect square.

    (x - 3) ^2 = 16

    Now we can subtract the coefficient back to the left.

    (x - 3) ^2 - 16 = 0
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