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17 January, 12:39

Solve the given system by the substitution method.

4x + 3y = 0

x - 2y = 0

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  1. 17 January, 12:45
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    solutio (0; 0)

    Step-by-step explanation:

    4x + 3y = 0 ... (1)

    x - 2y = 0 ... (2)

    multiply (2) by - 4 : - 4x + 8y = 0 ... (3)

    add (1) and (3) : 11y = 0 so : y = 0

    put y = 0 in (1) : 4x+3 (0) = 0

    4x = 0 so : x=0
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