Ask Question
19 July, 03:33

A triangular pennant has two sides that are 90 cm long each with an included angle of 25°.

What is the area of this pennant?

Enter your answer as a decimal in the box. Round only your final answer to the nearest tenth.

+1
Answers (1)
  1. 19 July, 04:02
    0
    We are given with the following value:

    AB = BC = 90 cm

    ∠B = 25°

    ∠D=90°

    Solving the ∠C:

    180 ° = (∠B/2) + ∠D + ∠C

    180° = (25°/2) + 90° + ∠C

    180° - 12.5° - 90° = ∠C

    ∠C = 77.5°

    Solving for length in mD:

    sin 77.5° = mD/90

    mD = 90 sin77.5°

    mD = 87.87

    Solving for mDC:

    cos 77.5 = mDC/90

    mDC = 90 cos 77.5°

    mDC = 19.48

    Area = 1/2 * Base * Height

    Area = 1/2 * 19.48*87.87

    Area = 855.834

    The total area of triangular pennant = 2 x 855.834 = 1,711.67 cm².

    The area is 1,711.67 cm².
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A triangular pennant has two sides that are 90 cm long each with an included angle of 25°. What is the area of this pennant? Enter your ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers