Identify the x-intercept and y-intercept of the line 4x-2y=-12

First let's put the equation into slope-intercept form ...

y = mx + b

4x - 2y = - 12

-2y = - 4x - 12

y = 2x + 6

In this form, the y intercept is represented by b (in this case 6).

Now if we set y = to zero in the equation, that will give us the x intercept ...

0 = 2x + 6

-6 = 2x

-3 = x

So we have ...

x Intercept = - 3

y intercept = 6

X intercept is where the line crosses the x axis or where y=0

y intercept is where the line crosses the y axis or where x=0

x intercept

set y=0 and solve

4x-2 (0) = - 12

4x=-12

x=-3

(-3,0) is x intercept

y intercept

set x=0 and solve

4 (0) - 2y=-12

-2y=-12

y=6

(0,6)

xint = (-3,0)

yint = (0,6)