The scale is set by Fs = 160.0 N. We release the block at x = 12 cm. How much work does the spring do on the block when the block moves from xi = + 8.0 cm to (a) x = + 5.0 cm, (b) x = - 5.0 cm, (c) x = - 8.0 cm, and (d) x = - 10.0 cm?

Question

Raven Salas

Mathematics

11 January, 15:29

The scale is set by Fs = 160.0 N. We release the block at x = 12 cm. How much work does the spring do on the block when the block moves from xi = + 8.0 cm to (a) x = + 5.0 cm, (b) x = - 5.0 cm, (c) x = - 8.0 cm, and (d) x = - 10.0 cm?

+3

Answers (1)

Know the Answer?

Camille Trujillo · Answer 1

Answer:a) 480Nm b) 2080Nm c) 2560Nm d) 2880Nm

Step-by-step explanation:

Work is said to be done when a force is applied to move an object through a particular distance.

Workdone=Force*distance

Force=160.0N

a) when a block moves from + 8cm distance to + 5cm, the total distance covered will be 3cm

Workdone=160*3 = 480Nm

b) when a block moves from + 8cm distance to - 5cm, the total distance covered will be + 13cm

Workdone=160*13 = 2080Nm

c) when a block moves from + 8cm distance to - 8cm, the total distance covered will be + 16cm

Workdone=160*16 = 2560Nm

d) when a block moves from + 8cm distance to - 10cm, the total distance covered will be + 18cm

Workdone=160*18 = 2880Nm