6 June, 13:13
The sum of 4 consqutive terms in an A P is 32 and the ratio of the product of the first and the last term of the product of two middle terms is 7:15 find th numbers?
6 June, 13:40
Four consecutive numbers are 2, 6, 10 and 14
15 (a² - 9d²) = 7 (a² - d²)
15a² - 135d² = 7a² - 7d²
15a² - 7a² = 135d² - 7d²
8a² = 128d²
Putting the value of a = 8 in above we get.
8 (8) ² = 128d²
128d² = 512
d² = 512/128
d² = 4
d = 2
So, the four consecutive numbers are
8 - (3*2)
8 - 6 = 2
8 - 2 = 6
8 + 2 = 10
8 + (3*2)
8 + 6 = 14
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» The sum of 4 consqutive terms in an A P is 32 and the ratio of the product of the first and the last term of the product of two middle terms is 7:15 find th numbers?