Ask Question

The sum of 4 consqutive terms in an A P is 32 and the ratio of the product of the first and the last term of the product of two middle terms is 7:15 find th numbers?

+1
Answers (1)
  1. 6 June, 13:40
    0
    Four consecutive numbers are 2, 6, 10 and 14

    Step-by-step explanation:

    15 (a² - 9d²) = 7 (a² - d²)

    15a² - 135d² = 7a² - 7d²

    15a² - 7a² = 135d² - 7d²

    8a² = 128d²

    Putting the value of a = 8 in above we get.

    8 (8) ² = 128d²

    128d² = 512

    d² = 512/128

    d² = 4

    d = 2

    So, the four consecutive numbers are

    8 - (3*2)

    8 - 6 = 2

    8 - 2 = 6

    8 + 2 = 10

    8 + (3*2)

    8 + 6 = 14
Know the Answer?