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23 November, 14:20

Sally has a photograph that has an area of 35 square inches. She creates 2 enlargements of the photograph. The enlargements have areas of 140 square inches and 560 square inches. In each photograph, the length is 1 2/5 times the width. Select which of thr following could be th dimensions of the original photograph or one of the enlargements. Mark all that apply

5 inches by 7 inches

20 inches by 28 inches

7 inches by 20 inches

21 inches by 15 inches

10 inches by 14 inches

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  1. 23 November, 14:38
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    The area of the photograph is:

    A = (w) * (l)

    Where,

    w: width

    l: long

    Substituting:

    35 = (w) * (1.4w)

    35 = 1.4 * w ^ 2

    w = root (35 / 1.4)

    Dimensions of the original photograph:

    w = 5 in

    l = 1.4 * (5) = 7 in

    Dimensions of extension 1:

    k = (140) / (35) = 4

    w = 4 * 5 = 20 in

    l = 4 * 7 = 28 in

    Dimensions of extension 2:

    k = (560) / (35) = 16

    w = 16 * 5 = 80 in

    l = 16 * 7 = 112 in

    Answer:

    5 inches by 7 inches

    20 inches by 28 inches
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