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2 September, 14:37

You have a coord grid that is 96x96. what is the minimum number of bits that you will need to encode a coordinate in that space

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  1. 2 September, 14:56
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    One bit can code 2 type of possibilities. That mean 1 bit code 2^1 possibilities, 2 bits code 2^2 possibilities and X amount of bits will code 2^X possibilities. In this case, you need to code 96x96 possibilities = 9216 possibilities. To answer this question, you need to find out how much it will be in 2^X form. The fast way to solve it by dividing it with 32 (2^5) until the value <32 then divide it with 2 (2^1) till it become <1

    9216/32 = 288

    288/32 = 9 - - >take the 1 extra to made it 8

    8/2 = 4

    4/2 = 2

    2/2=1

    1/2 = 0.5

    The number is divided by 32 two times and divided by 2 four times. Then the number of bits would be

    5*2 + 1*4 = 14 bits

    The answer will be 14 bits since 14 bits will code 16384 possibilities
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