4 February, 13:19
How do you factor: #y = 2x^3 - 32x #?
4 February, 15:18
Which two factors are common to both terms of the given expression?
One of those factors is 2; the other is x.
Thus, y = 2x^3 - 32x = 2x (x^2-16)
Also note that x^2-16 is easily factorable:
y = 2x (x-4) (x+4) (answer)
Know the Answer?
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» How do you factor: #y = 2x^3 - 32x #?