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2 January, 08:44

A. 0.6875b. 02275c. 0.0396d. 1.2222e. 0.0704f. 00576

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  1. 2 January, 08:59
    0
    The question has some details missing or incomplete. here is the complete part of the question; 18% of all students at West Colon High School play baseball and 32% play soccer. The probability that a student plays baseball given that the student plays soccer is 22%.

    a) Calculate the probability that a student plays both baseball and soccer.

    Step-by-step explanation:

    Let X = all students at West Colon High School play baseball

    Y = all students at West Colon High School play soccer

    Given P (X) = 0.18. P (Y) = 0.32, P (X|Y) = 0.22 but P (X|Y) = P (XnY) / P (B) Therefore, P (XnY) = P (X|Y) x P (B) therefore = the probability that a student plays both baseball and soccer P (XnY) = 0.22 x 0.32 = 0.0704

    The correct answer is option E
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