A flying objects height in the sky can be represented by the equation d=30+vt+4t^2 where d is the height in feet, v is the velocity in feet per second, and t is the time in seconds. How long has the flying object been traveling if it has velocity of 8 feet per second and has risen to a height of 126 feet? A: 4 seconds

B: 6 seconds

C: 8 seconds

D: 16 seconds

Question

Karissa Bates

Mathematics

31 May, 19:11

A flying objects height in the sky can be represented by the equation d=30+vt+4t^2 where d is the height in feet, v is the velocity in feet per second, and t is the time in seconds. How long has the flying object been traveling if it has velocity of 8 feet per second and has risen to a height of 126 feet? A: 4 seconds

B: 6 seconds

C: 8 seconds

D: 16 seconds

+4

Answers (1)

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Rory Fields · Answer 1

4 s

Step-by-step explanation:

d = 30 + vt + 4t²

v = 8 ft/s; d = 126 ft

126 = 30 + 8t + 4t² Subtract 126 from each side

4t² + 8t - 96 = 0 Divide each side by 4

t² + 2t - 16 = 0 Factor the equation

(t + 6) (t - 4) = 0

t + 6 = 0 t - 4 = 0

t = - 6 t = 4

We reject the negative time, so t = 4.

The object has been travelling for 4 s.