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20 September, 15:23

Solve the system by the elimination method.

2a + 3b = 6

5a + 2b - 4 = 0

+1
Answers (2)
  1. 20 September, 15:25
    0
    Make in form

    ax+by=c

    add 4 to both sides in 2nd equaiton

    5a+2b=4

    now

    elimiate a variable

    I choose b

    multiply top equation by - 2 and 2nd by 3

    add

    -4a-6b=-12

    15a+6b=12 +

    11a+0b=0

    11a=0

    a=0

    nice

    sub back

    5a+2b=4

    5 (0) + 2b=4

    2b=4

    divide 2

    b=2

    a=0

    b=2

    if in form (a, b)

    (0,2)
  2. 20 September, 15:51
    0
    2a + 3b = 6 - - > Equation 1

    5a + 2b = 4 - - > Equation 2

    Equation 1 * 5 - - > 10a + 15b = 30

    Equation 2 * 2 - - > 10a + 4b = 8

    Equation 1 - Equation 2 - - > 11b = 22 - - > b = 2

    Sub b=2 in Equation 1 (or 2, either works):

    2a + 3b = 6

    2a + 3 (2) = 6

    2a + 6 = 6

    2a = 0

    a = 0

    b = 2, a = 0
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