If the perimeter of the rectangle is 48, find the dimensions

P=perimeter

l=legnth

w=width

so perimiter of rectangle=legnth+legnth+width+widht or

p=2l+2w or undistribute the 2

p=2 (l+w)

if p=48 then

48=2 (l+w)

divide by 2

24=l+w

so the answer is l+w=24

l=24-w

w=l-24

subsitue

legnth>width

answeres could be:

L, W

23,1

22,2

21,3

20,4

19,5

18,6

17,7

16,8

15,9

14,10

13,11

and that is only the integer pairs