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24 September, 00:42

Using the equation for the line of the best fit, what is a good approximation for x when f (x) is equal to 30

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  1. 24 September, 01:03
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    Then the vertex is at (h, k) = (2, - 3) and the value of p is - 3. Since y is squared and p is negative, then this is a sideways parabola that opens to the left. This puts the focus 3 units to the left of the vertex.

    vertex: (2, - 3); focus: (-1, - 3)
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