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18 June, 21:23

Verify that (sinx - cosx) ^2=1-2sin (x) cos (x)

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Answers (2)
  1. 18 June, 21:26
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    (sinx - cosx) ^2 = (sinx) ^2 + (cosx) ^2 - 2sinxcosx = 1-2sinxcosx
  2. 18 June, 21:33
    0
    See below.

    Step-by-step explanation:

    Left side = (sinx - cosx) ^2 = sin^2 x + cos^2x - 2sinx cosx

    Now sin^2 x + cos^2 x = 1 so we have:

    1 - 2 sinx cosx = right side.
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