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31 July, 15:44

What is the variable y 3y+1=8y+16

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  1. 31 July, 15:47
    0
    3y+1=8y+16

    You must get "y" by itself

    Minus 3y from each side

    3y-3y+1=8y-3y+16

    1=5y+16

    Minus 16 from each side

    1-16=5y+16-16

    -15=5y

    Divide - 15 by 5y

    -15:5y=-3y

    y=-3
  2. 31 July, 15:58
    0
    3y + 1 = 8y + 16

    8y - 3y = - 16+1

    5y = - 15

    y=-3
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