a baseball diamond is square with each base 90 feet apart, Andy is starting on first base while his teammate Logan is standing between 2nd and 3rd base. if the straight line distance from Andy to Logan is 98 feet, how far is Logan standing from 2nd base? round your answer to the nearest tenth

Question

Asa Herring

Mathematics

16 September, 16:19

a baseball diamond is square with each base 90 feet apart, Andy is starting on first base while his teammate Logan is standing between 2nd and 3rd base. if the straight line distance from Andy to Logan is 98 feet, how far is Logan standing from 2nd base? round your answer to the nearest tenth

+5

Answers (2)

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Nasir · Answer 1

Logan is standing about 38.8 feet past 2nd base.

Step-by-step explanation:

a^2 + b^2 = c^2

90^2 + b^2 = 98^2

b^2 = 98^2 - 90^2

b^2 = 9604 - 8100

b^2 = 1504

b = 38.8

Lina · Answer 2

Logan is 45 feet from second base.

Step-by-step explanation:

If you divide 90 by 2 because is 1/2 away then it would be 45