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5 January, 02:17

Y=ax^2-bx-12. find the value of x? when a=1, b=2, y=3 by using general formular

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  1. 5 January, 02:25
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    Find the value of x when a=1, b=2, y = 3 by using general formula

    After replace number in a, b, y we have

    3 = 1ax^2 - 2x - 12

    x^2 - 2x - 15 = 0

    x^2 - 5x + 3x - 15 = 0

    (x^2 - 5x) + (3x - 15) = 0

    x * (x - 5) + 3 * (x - 5) = 0

    (x - 5) * (x + 3) = 0

    x - 5 = 0 or x + 3 = 0

    x=5 or x=-3
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