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19 November, 20:53

What is the solution to the equation e^3x=12 x=0.83 x=1.09 x=2.48 x=7.44

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  1. 19 November, 21:10
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    E^3x = 12

    log e^3x = log 12

    3x log e = log 12 [log e = 1]

    3x = log 12

    x = (log 12) / 3 = 0.83
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