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2 January, 14:38

If m^6=3/y and m^5=y^2/6 then which of the following expresses m in terms of y?

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Answers (2)
  1. 2 January, 14:51
    0
    M = (m^6) / (m^5) = (3/y) / (y^2/6) = (3/y) * (6/y^2) = 18/y^3
  2. 2 January, 14:57
    0
    M⁶ = 3/y and m⁵ = y²/6

    m⁶ = m⁵. m¹ = m¹⁺⁵ = m⁶

    m⁶ = m⁵. m = (y²/6). (m)

    3/y = m (y²/6)

    cross multiplication: m. y³ = 18

    m=18/y³
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