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19 July, 14:56

What is the inverse of the function f (x) = 8x+1? f^{-1} (x) =

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  1. 19 July, 15:05
    0
    Change the x and y

    Then solve for y

    X = 8y+1

    Subtract 1 from both sides

    X-1=8y

    Divide by 8

    X-1 / 8 = y
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