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31 October, 21:31

The lateral surface area of a right square pyramid is given by s - 82.492. If the pyramid has height 10 feet and lateral surface

area 100 square feet, what is the length of a side b of its base?

a. $6.92586 ft

C. 1.36523 ft

b. 4.85868 ft

d. 9.36369 ft

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Answers (1)
  1. 31 October, 21:40
    0
    a is the answer.

    Step-by-step explanation:

    S - 82.492 = Perimeter base x height / 2 + base

    Pyramid base

    b x 10h = hb / 2 + b = 100

    6.92586 x 6.92586 x 10 = 479.675367396/2 = 239.837683698 + base 47.9675367396 = 287.805220438

    479.675367396 - 287.805220438 = 191.870146958

    Proving each rectangle pyramid side is 1/4 of 287.805220438/4 = 72 + 10 height = S - 82 (S = 82.492)

    then 192/2 = 96 = 100 square feet
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