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19 October, 17:16

David found and factored out the GCF of the polynomial 80b4 - 32b2c3 + 48b4c. His work is below.

GFC of 80, 32, and 48: 16

GCF of b4, b2, and b4: b2

GCF of c3 and c: c

GCF of the polynomial: 16b2c

Rewrite as a product of the GCF:

16b2c (5b2) - 16b2c (2c2) + 16b2c (3b2)

Factor out GCF: 16b2c (5b2 - 2c2 + 3b2)

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Answers (1)
  1. 19 October, 17:24
    0
    If you will simplify his answer 16b2c (5b2 - 2c2 + 3b2) you will get

    80b ⁴c - 32b²c³ + 48b³c, which is not equivalent to 80b4 - 32b2c3 + 48b4c.

    So can you add more details?
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