Find the possible value or values of y in the quadratic equation 4 - 4y - y 2 = 0. A. y = - 3, y = - 1 B. y = 2 C. y = - 2 + 2√ 2, y = - 2 - 2√ 2 D. y = - 4, y = 1

Question

Adeline Garrison

Mathematics

31 January, 05:36

Find the possible value or values of y in the quadratic equation 4 - 4y - y 2 = 0. A. y = - 3, y = - 1 B. y = 2 C. y = - 2 + 2√ 2, y = - 2 - 2√ 2 D. y = - 4, y = 1

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Kristina Armstrong · Answer 1

4 - 4y - y² = 0

-y² - 4y + 4 = 0

y = - (-4) ± √ ((-4) ² - 4 (4) (-1))

2 (-1)

y = 4 ± √ (16 + 16)

-2

y = 4 ± √ (32)

-2

y = 4 ± 4√ (2)

-2

y = 4 + 4√ (2) or y = 4 - 4√ (2)

-2 - 2

y = - 2 - 2√ (2) or y = - 2 + 2√ (2)

The answer is C.