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Victoria Hardy
Mathematics
30 July, 21:24
SecA=√6.00, find tanA
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Kayley Khan
30 July, 21:28
0
tan (A) = √5
Step-by-step explanation:
The relation between secant and tangent is ...
tan² (A) + 1 = sec² (A)
Then ...
tan (A) = √ (sec² (A) - 1) = √ (6 - 1)
tan (A) = √5
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