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7 March, 07:57

Susan throws a softball upward into the air at a speed of 32 feet per second from a 88 dash foot88-foot platform. the distance upward that the ball travels is given by the function d left parenthesis t right parenthesis equals negative 16 t squared plus 32 t plus 88d (t) = - 16t2+32t+88. what is the maximum height of the softball? how many seconds does it take to reach the ground after first being thrown upward? (round your answer to the nearest tenth.)

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  1. 7 March, 08:08
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    D (t) = - 16t²+32t+88

    a] Maximum height

    At maximum height d' (t) = 0

    from d (t);

    d' (t) = - 32t+32=0

    thus

    t=1

    hence the maximum height will be:

    d (t) = - 16t²+32t+88

    d (1) = - 16 (1) ^2+32 (1) + 88

    d (1) = 104 ft

    2] how many seconds does it take to reach the ground after first being thrown upward?

    Here we solve for t intercept

    when d (t) = 0

    thus

    0=-16t²+32t+88

    solving for t, we get:

    t=1 - √13/2

    or

    t=1 + √13/2

    t=-1.55 or t=3.55 sec

    Thus the answer is t=3.55 sec
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