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Zoie Hatfield
Mathematics
6 June, 21:09
Solve the system below using any method:
X+2y=1
5x-4y=-23
+5
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2
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Jax Abbott
6 June, 21:11
0
X+2y=1
2y = 1-x
y = (1-x) / 2
5x-4y = - 23
By substituting the value of y in this equation
5x - 4 { (1-2) / 2} = - 23
5x - 2 + 2x = - 23
7x = - 21
x = - 3
Now, let's find the value of y bu putting the value in any othe two equations
I'll use x + 2y=1
-3 + 2y=1
2y = 4
y=2
So, the value of x and y is - 3 and 2 respectively.
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Pamela Glass
6 June, 21:26
0
I'll use substitute method.
x + 2y = 1. (1)
5x - 4y = - 23. (2)
from 1,
x = 1 - 2y. (3)
then I'll substitute (3) into 2,
5 (1-2y) - 4y = - 23. (this way we only need to calculate y, as x is isolated out)
5 - 10y - 4y = - 23
5 - 14y = - 23
-14y = - 28
y = 2
now we can substitute y = 2 back into (3)
x = 1 - 2 (2)
x = - 3
therefore we get that x is - 3 and y is 2.
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