What is the product?

(4y-3) (2y^2+3y-5)

8y^3 + 6y^2 - 29y + 15

Step-by-step explanation:

8y^3 + 12y^2 - 20y - 6y^2 - 9y + 15

then

8y^3 + 6y^2 - 29y + 15 is the product

Best regards

=8y^3+6y^2-29y+15

Step-by-step explanation:

(4y-3) (2y^2+3y-5)

= (4y+-3) (2y^2+3y+-5)

= (4y) (2y^2) + (4y) (3y) + (4y) (-5) + (-3) (2y^2) + (-3) (3y) + (-3) (-5)

=8y^3+12y^2-20^y-6y^2-9y+15

=8y^3+6y^2-29y+15