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Brittany Flynn
Mathematics
22 April, 09:53
What is the product?
(4y-3) (2y^2+3y-5)
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Eli Singleton
22 April, 09:59
0
8y^3 + 6y^2 - 29y + 15
Step-by-step explanation:
8y^3 + 12y^2 - 20y - 6y^2 - 9y + 15
then
8y^3 + 6y^2 - 29y + 15 is the product
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Everett Pace
22 April, 10:07
0
=8y^3+6y^2-29y+15
Step-by-step explanation:
(4y-3) (2y^2+3y-5)
= (4y+-3) (2y^2+3y+-5)
= (4y) (2y^2) + (4y) (3y) + (4y) (-5) + (-3) (2y^2) + (-3) (3y) + (-3) (-5)
=8y^3+12y^2-20^y-6y^2-9y+15
=8y^3+6y^2-29y+15
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