How many different ways could eight students sit in a semicircle to watch an experiment?

40,320

5,040

8

To answer this you need to do the factorial for 8 which is 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1 and you'll get the number of combinations that is 40,320 because that's the possible number of combinations.