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23 October, 08:54

Express the sum or difference as a product

Sin 4x - sin6x

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  1. 23 October, 09:09
    0
    Just apply the formula

    sinα - sinβ = 2sin[ (α-β) / 2] x cos[ (α+β) / 2]

    sin4x - sin6x = 2sin[ (4x - 6x) / 2]. cos[4x+6x) / 2]

    sin4x - sin6x = 2sin (-x). cos5x

    sin4x-sin6x = - 2sinx. cos5x
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