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7 July, 17:10

What is the range f (x) = x^2 - 2x-5 when the domain is {1,2}?

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  1. 7 July, 17:21
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    X^2-2x-5 = (x-1) ^2-6

    After substituting we get that the domain is:

    {-6; -5}
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