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25 May, 03:59

Solve and graph the absolute value inequality: |2x + 1| ≤ 5.

A. number line with closed dots on negative 3 and 2 with shading going in the opposite directions.

B. number line with closed dots on negative 3 and 2 with shading in between.

C. number line with open dots on negative 3 and 2 with shading in between.

D. number line with closed dots on negative 2 and 2 with shading in between.

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  1. 25 May, 04:17
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    |2x + 1| < = 5

    -5 < = 2x + 1 < = 5 ... subtract 1

    -5 - 1 < = 2x + 1 - 1 < = 5 - 1

    -6 < = 2x < = 4 ... divide by 2

    -6/2 < = (2/2) x < = 4/2

    -3 < = x < = 2

    B. a number line with closed dots (because of the = sign) on - 3 and 2 with shading in between
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