Gabriel is using logarithms to solve the equation 52x = 27. Which of the following equations would be equivalent to his original expression?

5 log 2x = log 27

2 log 5 = x log 27

x log 5 = 2 log 27

2x log 5 = log 27

Question

Cooper

Mathematics

16 May, 23:08

Gabriel is using logarithms to solve the equation 52x = 27. Which of the following equations would be equivalent to his original expression?

5 log 2x = log 27

2 log 5 = x log 27

x log 5 = 2 log 27

2x log 5 = log 27

+5

Answers (1)

Know the Answer?

Clara Yu · Answer 1

Hello

5^ (2x) = 27

if : a>0 and b>0 a = b equivalent to log (a) = log (b)

log (5^ (2x)) = log (27) ... (1)

a>0 and b>0 log (a^n) = nlog (a)

(1) equivalent to : 2x log 5 = log 27

Gabriel is using logarithms to solve the equation 52x = 27. Which of the following equations would be equivalent to his original expression?5 log 2x = log 272 log 5 = x log 27x log 5 = 2 log 272x log 5 = log 27

Gabriel is using logarithms to solve the equation 52x = 27. Which of the following equations would be equivalent to his original expression?

5 log 2x = log 27

2 log 5 = x log 27

x log 5 = 2 log 27

2x log 5 = log 27