A bicycle manufacturing company knows that the equation R=-2.5p? + 500 p models

the relationship between the price (p) and the revenue (R) for one of its product lines.

What is the maximum revenue possible?

$

The maximum revenue is $25,000

Step-by-step explanation:

The model equation is;

R = - 2.5p^2 + 500p

To find the maximum value, we differentiate this and set result = 0

The first differential of this model equation is - 5p + 500

we set this to zero to get the maximum price

5p = 500

p = 500/5

p = 100

Now to get the maximum revenue, we simply substitute the value of the maximum price

That would be - 2.5 (100) ^2 + 500 (100)

= - 2.5 (10,000) + 50,000

= 25,000 + 50,000

= 25,000