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Isabel Vargas
Mathematics
19 June, 01:01
If dy/dx = 2xy^2, what is d^2y/dx^2?
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Amaris Graves
19 June, 01:18
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Y'' = d^2 y / d x^2
= 2 (x y' + y. 1)
= 2x. y' + 2y
= 2x (2 xy) + 2y ... from (1)
= 4 x^2 y + 2y
= 2y (2 x^2 + 1)
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