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29 August, 15:07

A 90 k g shopper is standing on an escalator that makes a 25 ∘ incline with the horizontal. The escalator carries the shopper to the next floor, a height 30 m above ground level, at a constant speed. Calculate the work that the escalator does on the shopper.

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  1. 29 August, 15:28
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    W = 27 k J

    Step-by-step explanation:

    Given that

    mass, m = 90 kg

    Height, h = 30 m

    angle, θ = 25°

    The work done by escalator is given as follows

    W = m g h

    Work done by escalator does not depends on the angle, it depends only on height.

    Now by by putting the values in the above equation we get

    W = 90 x 10 x 30 J (take g = 10 m/s²)

    W = 27000 J

    W = 27 k J

    Therefore work done by escalator will be 27 k J.
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