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24 January, 12:32

How many no real complex roots does the polynomial f (x) = x^4 - x^2 - 12 have?

A. 0

B. 1

C. 2

D. 3

E. 4

+2
Answers (1)
  1. 24 January, 12:40
    0
    Answer: 2 real roots 2 complex roots Step-by-step explanation:

    f (x) factors as ...

    ... f (x) = (x² - 4) (x² + 3) = (x - 2) (x + 2) (x² + 3)

    The real roots are x = ±2.

    The complex roots are x = ±i√3.

    ___

    We don't know what "no real complex roots" means. We suspect your answer may be C. 2.
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