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26 August, 04:51

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. Match each equation with the operation you can use to solve for the variable. Subtract 10. Divide by 10. Divide by 5. Subtract 18. Multiply by 10. Add 18. Add 10. Multiply by 5. 5 = 10p arrowRight p + 10 = 18 arrowRight p + 18 = 5 arrowRight 5p = 10 arrowRight

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  1. 26 August, 05:01
    0
    1 & b

    2 & a

    3 & d

    4 & c

    Step-by-step explanation:

    a. subtract 10

    b. divide by 10

    c. divide by 5

    d. subtract 18

    e. multiply by 10

    f. add 18

    g. add 10

    h. multiply by 5

    1. 5 = 10p

    2. p + 10 = 18

    3. p + 18 = 5

    4. 5p = 10
  2. 26 August, 05:17
    0
    The quadratic equations and their solutions are;

    9 ± √33 / 4 = 2x² - 9x + 6.

    4 ± √6 / 2 = 2x² - 8x + 5.

    9 ± √89 / 4 = 2x² - 9x - 1.

    4 ± √22 / 2 = 2x² - 8x - 3.

    Explanation:

    Any quadratic equation of the form, ax² + bx + c = 0 can be solved using the formula x = - b ± √b² - 4ac / 2a. Here a, b, and c are the coefficients of the x², x, and the numeric term respectively.

    We have to solve all of the five equations to be able to match the equations with their solutions.

    2x² - 8x + 5, here a = 2, b = - 8, c = 5. x = - b ± √b² - 4ac / 2a = - (-8) ± √ (-8) ² - 4 (2) (5) / 2 (2) = 8 ± √64 - 40/4. 24 can also be written as 4 * 6 and √4 = 2. So x = 8 ± 2√6 / 2*2 = 4±√6/2.

    2x² - 10x + 3, here a = 2, b = - 10, c = 3. x = -b ± √b² - 4ac / 2a = - (-10) ± √ (-10) ² - 4 (2) (3) / 2 (4) = 10 ± √100 + 24/4. 124 can also be written as 4 * 31 and √4 = 2. So x = 10 ± 2√31 / 2*2 = 5 ± √31 / 2.

    2x² - 8x - 3, here a = 2, b = - 8, c = - 3. x = - b ± √b² - 4ac / 2a = - (-8) ± √ (-8) ² - 4 (2) (-3) / 2 (2) = 8 ± √64 + 24/4. 88 can also be written as 4 * 22 and √4 = 2. So x = 8 ± 2√22 / 2*2 = 4± √22/2.

    2x² - 9x - 1, here a = 2, b = - 9, c = - 1. x = - b ± √b² - 4ac / 2a = - (-9) ± √ (-9) ² - 4 (2) (-1) / 2 (2) = 9 ± √81 + 8/4. x = 9 ± √89 / 4.

    2x² - 9x + 6, here a = 2, b = - 9, c = 6. x = - b ± √b² - 4ac / 2a = - (-9) ± √ (-9) ² - 4 (2) (6) / 2 (2) = 9 ± √81 - 48/4. x = 9 ± √33 / 4

    To match we solve the monomials.

    1. - 15u^3 + 5u^3

    Adding

    -15u^3 + 5u^3=-10u^3

    2. 10u^3 + (-5u^3)

    Adding

    10u^3-5u^3=5u^3

    3. 10u^3 + 5u^3

    Adding

    10u^3 + 5u^3=15u^3

    4. 5u^3 + (-10u^3)

    Adding

    5u^3-10u^3 = -5u^3

    Two separate ways to find the answers.
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