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Mathematics
27 December, 18:41
Factor completely (3x^2-12x) (x^2-2x+1) =
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Sebastian Warren
27 December, 19:03
0
3x^4-18x^3+27x^2-12x
Step-by-step explanation:
Multiply the second paréntesis for each term of the first parentage
3x^2 * (x^2-2x+1) - 12x * (x^2-2x+1)
Multiply parentage by 3x^2
3x^4-6x^3+3x^2-12x * (x^2-2x+1)
Multiply the parentage by - 12x
3x^4-6x^3+3x^2-12x^3+24x^2-12x
Group similar terms
3x^4-18x^3+27x^2-12x
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