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Alessandro
Mathematics
14 October, 22:31
3x-2 ≤4x+8 inequalities
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Quincy
14 October, 22:38
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Solve it the same way as if you'd solve a regular equation
try to get all the variable terms onto one side and the constant terms on the other.
moving the x to the right side, i would subtract by 3x
3x-2 - 3x≤ 4x+8-3x
since
3x-3x = 0
then
-2 ≤ 4x - 3x + 8
add up like terms (or subtract)
-2 ≤ (4x - 3x) + 8
-2 ≤ x + 8
now move the constants onto the left side, this could be done by subtracting 8 to boh sides
-2 - 8 ≤ x + 8-8
8-8=0
so
-2-8 ≤ x
add up like terms (or subtract)
-10 ≤ x
and flip it if you want the x term to be on the left
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