Factor the polynomial.

2y2 - 14y + 20

A. (y + 2) (y + 5)

B. 2ly - 2) (y + 5)

C. (y-2) (x - 5)

D. 2 (y-2) (y-5)

2y^2 - 14y + 20

By splitting the middle term:

2y^2 - 10y - 4y + 20

By taking the common outside:

2y (y-5) - 4 (y-5)

= (2y-4) (y-5)

=2 (y-2) (y-5)

Therefore D is the right answer

D

Step-by-step explanation:

Given

2y² - 14y + 20 ← factor out 2 from each term

= 2 (y² - 7y + 10)

To factor the quadratic

Consider the factors of the constant term ( + 10) which sum to give the coefficient of the y - term ( - 7)

The factors are - 2 and - 5, since

- 2 * - 5 = 10 and - 2 - 5 = - 7, so

y² - 7y + 10 = (y - 2) (y - 5) and

2y² - 14y + 20 = 2 (y - 2) (y - 5) → D