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14 July, 03:07

Factor the polynomial.

2y2 - 14y + 20

A. (y + 2) (y + 5)

B. 2ly - 2) (y + 5)

C. (y-2) (x - 5)

D. 2 (y-2) (y-5)

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Answers (2)
  1. 14 July, 03:12
    0
    2y^2 - 14y + 20

    By splitting the middle term:

    2y^2 - 10y - 4y + 20

    By taking the common outside:

    2y (y-5) - 4 (y-5)

    = (2y-4) (y-5)

    =2 (y-2) (y-5)

    Therefore D is the right answer
  2. 14 July, 03:26
    0
    D

    Step-by-step explanation:

    Given

    2y² - 14y + 20 ← factor out 2 from each term

    = 2 (y² - 7y + 10)

    To factor the quadratic

    Consider the factors of the constant term ( + 10) which sum to give the coefficient of the y - term ( - 7)

    The factors are - 2 and - 5, since

    - 2 * - 5 = 10 and - 2 - 5 = - 7, so

    y² - 7y + 10 = (y - 2) (y - 5) and

    2y² - 14y + 20 = 2 (y - 2) (y - 5) → D
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